x^2+2x+160=0

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Solution for x^2+2x+160=0 equation: 



x^2+2x+160=0

a = 1; b = 2; c = +160;
Δ = b2-4ac
Δ = 22-4·1·160
Δ = -636
Delta is less than zero, so there is no solution for the equation

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